Pasar De Gramos A Moles Ejercicios Resueltos
Si en un vaso se tiene 150 ml de alcohol (etanol) cuya densidad es 0,8 g/ml. ¿cuántas moles de etanol hay en dicho volumen?
1. Si en un vaso se tiene 150 ml de alcohol (etanol) cuya densidad es 0,8 g/ml. ¿cuántas moles de etanol hay en dicho volumen?
Los moles en el compuesto de etanol son :
1,875 molExplicaciónMasa
ρ = m/V
0,8 g/mL = m/150 mL
m = 0,8 g/mL × 150 mL
m = 120 gramos
Moles
= m / Mr C2H5OH
= 120 gramos / (Ar C (2) + Ar H (5) + Ar O + Ar H)
= 120 gramos / (12 (2) + 1(5) + 16 + 1)
= 120 gramos / (24 + 5 + 16 + 1)
= 120 gramos / 64 gramos/mol
= 1,875 mol
Obtenga más información en este enlace:
https://brainly.co.id/tugas/20778831, https://brainly.co.id/tugas/10128762, https://brainly.co.id/tugas/11137183Detalles de mi respuesta Lección : QuímicaCapítulo: EstequiometríaClase: XSemestre 2Código: 10.7.9Palabras clave: fracción molar, moles de solvente, moles de soluto, Mr, Ar2. apa yang dimaksud dengan capsulae moles
adalah capsul lunak yg satu kesatuan,isi biasan nya cair, dapat juga padat bisa oral vaginal, rectal, topikal bentuknya bermacam-macam
3. apa yang dimaksud dengan capsulae moles
adalah kapsul lunak yang
- satu kesatuan
- selalu sudah terisi
- isi biasanya cair, dapat juga padat
- bisa oral, vaginal, rectal, topikal
- bentuknya bermacam - macam
4. Two moles of aluminum consist of...... atoms (L = 6.02 x 10^23)
x = n x L
x = 2 x 6,02 x 10^23
x = 12,02 x 10^23
x = 1,202 x 10^24
5. Consider the reaction for the commercial preparation of ammonia ; synthesis of ammonia (NH3) from the reaction between nitrogen and hydrogen. a) How many moles of hydrogen are needed to prepare 312 moles of ammonia? b) How many grams of hydrogen is this?
11010292928822
Penjelasan:
soriy ttayqyquq
6. Two moles of aluminum consist of...... atoms (L = 6.02 x 10^23)
x = n x L
x = 2 x 6,02 x 10^23
x = 12,02 x 10^23
x = 1,202 x 10^24
7. How many moles are there in44g of CO2? How many molecus is this
simply the molar mass of co2 is 44g/mol. It is calculated as below;
molar mass of c = 12 g/mol
molar mass of o= 16 g/mol
molar mass of co2= molar mass of c+ 2(molar mass of o)= (12+16+16)g/mol=44g/mol
number of moles = the given mass / molar mass of co2
number of moles= 44 g / 44 g/mol =1 mol
therfore 44g of co2 have 1 mole of co2 in it.
8. How many molecules of CO2 are the in 4.56 moles of CO2 ?
° STOIKIOMETRI °
Given
n = 4,56 moleL = 6,02 • 10²³Ask
X = ?Answer
To answer this question, we can use mole concept.
[tex] \Boxed {X = n \cdot L} [/tex]
So the answer
[tex] X = n \cdot L \\ X = 4,56 \cdot 6,02 \cdot 10^{23} \\ X \approx 2,75 \cdot 10^{23} [/tex]
9. For the given reaction C5H12 + 8 O2 → 5 CO2 + 6 H2O, If the reactants C5H12 & O2 are having 2 moles an 8 moles of initial feed respectively. How many moles of C5H12 are there when the reaction completes?
Jawaban:
1 mol C5H12
Penjelasan:
pakai cara yang di gambar ya
semoga bermanfaat
10. The number of moles of solute present in 1 kg of a solvent is called its A. Molality B. Molarity C. Normality D. Formality
A. Molality
pembahasan :
pertanyaannya adalah jumlah mol di larutan yang ada pada 1 kg pelarut disebut apa, jawabannya ada molalitas yaitu (n). sedangkan, molaritas (M) adalah konsentrasi suatu zat pada larutan tertentu.
11. what number of Fe atoms and what amount (moles) of Fe atoms are in 500.0 g of iron
STOICHIOMETRY :
It is known that the mass of Fe (Iron) we have is 500.0g and if we open the periodic table, it is also told that the relative atomic mass (Ar) is equal to approximately 56. So in this case we can find the mole of the iron with :
[tex]n = \frac{m}{Ar/Mr}[/tex]
Where :
n = mole
Ar/Mr = Relative Atomic Mass / Relative Molecular Mass
m = mass
So..
[tex]n = \frac{500}{56} = 8.92 ≈ 9 moles[/tex]
So the answer is 8,92 moles of Fe or approximately 9 moles of Fe
Hope it helps, Shalom!
12. how many moles of water is 5.87 x 10 22 molecules ?
Saya jawabnya pakai bahasa indonesia ya :p
Diketahui : Jumlah partikel : 5.87 x [tex]10^{22}[/tex]
Jumlah partikel = mol x L (bilangan avogadro)
5.87 x [tex]10^{22}[/tex] = mol x 6.02 x [tex]10^{23}[/tex]
mol = 0.097 mol
Semoga membantu :D
13. How many molecules of CO2 are the in 4.56 moles of CO2 ?
Jawaban:
Thus, the number of molecules of carbon dioxide is 6.23×1022 molecules 6.23 × 10 22 molecules .
14. 0.08 moles of sulfuric acid in 2 litres of solution has a Ph?
n (moles) = M / V
M (concentracion) = n x V = 0,08 moles x 2 Litres = 0,16 M
Since H₂SO₄ is strong acid, we must use this formula:
[H⁺] = acid valence x Concentration
[H⁺] = 2 x 0,16 M
[H⁺]= 0,32 M = 32 x 10⁻² M
pH = - log [H⁺]
pH = - log (32 x 10⁻² M)
pH = 2 - log 32
~apply some logarithm properties~
pH = 2 - 5 log 2
pH = 0,5
That gives us pH of said acid is 2-5log2.
I hope this helps~
15. calculate the number of moles of hydrochloric acid required to react exactly with 4.15 g sodium carbonate
Reaksinya jika HCl dalam bentuk larutan dengan padatan Na2CO3 :
2HCl + Na2CO3 ==> H2CO3 + 2 NaCl
Reaksinya jika HCl dalam bentuk cair dengan padatan Na2CO3 :
2HCl + Na2CO3 ==> 2NaCl + H2O +CO2
n Na2CO3 = m Na2CO3 ÷ Mr Na2CO3 = 4,15 g÷ 106 g/mol = 0,04 mol
n HCl = (koefisien HCl÷koefisien Na2CO3)× n Na2CO3 = (2÷1)×0,4 mol
= 0,8 mol
Jadi jumlah HCl yang dibutuhkan adalah 0,8 mol
16. -Q*Today is wednesday, what day was yesterday?*Today is wednesday, tomorrow will be...nt: cool because of moles '_'
Jawaban:
Tuesday
Thursday
thank u '-'
Answer:
1). Today is wednesday, what day was yesterday?
answer: Tuesday
2). Today is wednesday, tomorrow will be...
answer: Thursday
explanation:
hm _-
hope it's useful^^
17. How many moles of sodium bromide can be formed from 1.55 moles of aluminum bromide?
Jawaban:
12020729629101
Penjelasan:
kalo salah maap
18. Two moles of aluminum consist of...... atoms (L = 6.02 x 10^23)
x = n x L
x = 2 x 6,02 x 10^23
x = 12,02 x 10^23
x = 1,202 x 10^24
19. Find the number of moles of the indicated species: a) 333 mg of Na2B4O7.10H20
Jawaban:
Penjelasan:
[tex]\text{Na}_2\text{B}_4\text{O}_7.10\text{H}_2\text{O}[/tex]
Mr = 2Na + 4B + 8O + 20H
Mr = 2(23) + 4(11) + 17(16) + 20(1)
Mr = 46 + 44 + 272+ 20
Mr = 382
[tex]n = \frac{m}{Mm}\\n = \frac{333}{382}\\n = 0,87 \times 10^-3 \ \text{mol}[/tex]
20. What is the molarity of a solution containing 4 moles of KCl in 2.5 L of solution?
Penjelasan:
dik : n KCl = 4 mol
v = 2,5 L
dit : M = ?
jb :
M = n / v
= 4 mol / 2,5 L
= 1,6 mol/L
semoga membantu :)
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